4x^2+70x+114=0

Solution for 4x^2+70x+114=0 equation:

4x^2+70x+114=0

a = 4; b = 70; c = +114;
Δ = b2-4ac
Δ = 702-4·4·114
Δ = 3076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3076}=\sqrt{4*769}=\sqrt{4}*\sqrt{769}=2\sqrt{769}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{769}}{2*4}=\frac{-70-2\sqrt{769}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{769}}{2*4}=\frac{-70+2\sqrt{769}}{8}
$